α = 51.84° (normal value angle at giza) father
β = 58.52° unknown son
γ = 69.64° unknown mother
can you give me the celestial coordinates if we are at giza in the pyramid capstone...and with this triangle*4faces like that you can do the calculations....and I will tell you why this is very interesting!...
holy clock! be ready!
perimeter=2556
0.6178448867536 is like an approach on the "golden ratio".
good luck this is your homework for today! i will be very happy to share with you the rest of the story!
α = arccos[(b² + c² − a²) ÷ 2bc]
α = arccos[(846² + 930² − 780²) ÷ (2 × 846 × 930)]
α = arccos[0.6178448867536]
α = 51.84°
β = arccos[(a² + c² − b²) ÷ 2ac]
β = arccos[(780² + 930² − 846²) ÷ (2 × 780 × 930)]
β = arccos[0.52218362282878]
β = 58.52°
γ = arccos[(a² + b² − c²) ÷ 2ab]
γ = arccos[(780² + 846² − 930²) ÷ (2 × 780 × 846)]
γ = arccos[0.34795417348609]
γ = 69.64°
β = 58.52° unknown son
γ = 69.64° unknown mother
can you give me the celestial coordinates if we are at giza in the pyramid capstone...and with this triangle*4faces like that you can do the calculations....and I will tell you why this is very interesting!...
holy clock! be ready!
perimeter=2556
0.6178448867536 is like an approach on the "golden ratio".
good luck this is your homework for today! i will be very happy to share with you the rest of the story!
α = arccos[(b² + c² − a²) ÷ 2bc]
α = arccos[(846² + 930² − 780²) ÷ (2 × 846 × 930)]
α = arccos[0.6178448867536]
α = 51.84°
β = arccos[(a² + c² − b²) ÷ 2ac]
β = arccos[(780² + 930² − 846²) ÷ (2 × 780 × 930)]
β = arccos[0.52218362282878]
β = 58.52°
γ = arccos[(a² + b² − c²) ÷ 2ab]
γ = arccos[(780² + 846² − 930²) ÷ (2 × 780 × 846)]
γ = arccos[0.34795417348609]
γ = 69.64°