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Standard Teotihuacan Unit (no replies)

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While I wrote my first website essay regarding the Hugh Harleston Jnr, STU, {Standard Teotihuacan Unit} I commenced with the following

Quote
“The straightforward method is to divide the…:”1,924,582 square meters by the 1,714,608 square STU = 756 X 2,268 STU.” …to obtain: 1.1224618105129… the square root of this is: 1.0594629821343…the STU. The feet/metres ratio is: 1 ÷ 0.3048 = 3.2808398950131…the feet in one metre, hence 1.0594629821343…÷ 0.3048 x 12 = 41.7111410289104… {There are 43560 square feet in one acre, therefore a “near-miss” is: 43.56 x Pi x 0.3048 = 41.71120212186…}

Hence: the 1,924,582 x 0.3048 = 586612.5936 the 1,714,608 x 0.3048 = 522612.5184 in that case 586612.5936 x 522612.5184 = 306571084866.45172224 this is the square yards in one acre: 4840 x 63341133.2368701905454 this is 16000 x 3958.820827304…a tolerable Earth Polar radius given that 2 x 3958.820827304…x Pi = 24874.0048558…this is but 14.1847668298448…miles more than 24859.820089… an enhanced Earth Polar radius since it is 2 x Pi x 3956.56325154…”
Unquote

And yet with all due respect to Hugh Harleston, Jr., the 41.7111410289104…is not in line with the NC {Numerical Canon} Units of Measure employed within different eras via different cultures, however all completely interrelate. Therefore, I respectfully suggest the following may prove of advantage since all the Maya Calendar “numbers” gel, not only with each other, so to speak, they gel with diverse eras, diverse cultures, and the Units of Measure as and by whom they were employed, as I hope to demonstrate, since I currently calculated that the Maya 5256 ÷ 126 = 41.714285…the Maya STU

The 41.714285… divided by the NC {Numerical Canon} distance Earth to Sun of 93,312,000 Miles obtains 4.47040956300215…obviously increased since my PC issues a practically undecipherable “number” In any case the Maya STU divided by 93,312,000 denoted as M for Maya. The Earth calculation will obviously indicate: M is 93,312,000 x 41.714285…The numbers that follow the multiplication by 183708 are multiples of 365 Gematria Abraxas, Mithras, both Solar “gods”, likewise Maya Temples having 91 steps on each of their four sides hence 91 x 4 = 364 that added to the actual top platform, coning as 1 = 365

The 365 x 14.4 = 5256, likewise the Sothic Cycle of 1460 is 4 x 365 x the Maya Synodic period of Venus 584 is 1.6 x 365, equally Gematria Son of Man” 2190 is 6 x 365 Therefore they are likewise ratios of the 5256 since, for example, 5256 is 3.6 x 1460 and so on. The Maya Long Count of 1360800 is 5256 x 258.90410958…that multiplied by 756,864,000,000 = 195,955,200,000,000 the Nineveh Constant, hence 756,864,000,000 is 365 x 2,073,600,000, a Cubit attributed to Sir Isaac Newton being 2.0736, there is ample scope regarding 756,864,000,000 since we espy 756 and 864 within

Equally the Maya Long Count of 1360800 is too alike Gematria 3168 “Lord Jesus Christ” to ignore hence 1360800 ÷ 3168 = 429.5454…which is 375 Egyptian Feet of 1.14545…the 375 x 5256 = 1971000 which is the Sothic Cycle of 1460 x 1350

Therefore Nineveh 195,955,200,000,000 is 3168 x 1360800 x 45454.5454…The GP volume of 91,445,760 Cubic Feet divided by this 45454.5454…obtains exactly 2011.80672 which is exactly 1984.5 Longer value Greek Feet of 1.01376 consequently 1984.5 is 365 x 5.436986301…that multiplied by the Maya 5256 = 28576.8 which multiplied by 20 = 571536 Square Feet, the GP base area {756 x 756}
The GP base side-length of 756 Feet x 259,200,000,000 = 195,955,200,000,000 Likewise the Maya:1360800 {9.9.0.0.0} x 144,000,000 = 195,955,200,000,000

The Hugh Harleston, Jr., indicated: 756 x 2,268 STU is created via dividing the Nineveh Constant 195,955,200,000,000 by 86,400,000,000 to obtain 2,268

Hence the whole Units of Measure employed within separate eras by diverse cultures interconnect perfectly, one more example then we obtain the Planets data. The Atlantis area, minus the central Shrine, of 4,561,920,000 Square Cubits is the GP base area of 571536 x 7981.8594104…that divided by the Maya Year {1872000 ÷ 5130} of 364.9122807017…= 21.8733647305…that multiplied by 1,674,036,000 = 36,616,800,000 which is the Maya Long Count of 1360800 x 26908.289241…that divided by the GP Tan {480:378} of 1.269841…= 21190.2777…and this is exactly 11919.53125 x 1.777…the Square Root of the Rhind Papyrus fraction {256:81} of 3.160493827… and the 1,674,036,000 is GP base area of 571536 x 2929.012345679…that multiplied by 32.4 = 94900 which is the 365 x 260 the Maya Calendar “number”

The 11919.53125 multiplied by a component of the Comma of Pythagoras {531441:524288} namely 524288 = 6249267200, this, for example is the Atlantis 4,561,920,000 x 1.36987654320…that multiplied by the British Admiralty Nautical Mile of 6080 then by 81 obtains exactly 674636.8 that divided by the Eye of Horus fraction {64:63} of 1.015873…= 664095.6 which is the Maya STU of 41.714285…multiplied by exactly 15920.1 that is the Metonic, Cycle, Gematria “Eve” and a prime number: 19 x 837.9 which is Gematria “Weapons of god” 665 x 1.26, the STU of 41.714285…is 5256 ÷ 126

Equally since the Eye of Horus fraction of 1.015873…x 1.25 = 1.269841…we may well remain here forever and the proverbial day, yet the Planets beckon, we began with the Maya STU of 41.714285…and concluded with the Maya STU of 41.714285…with a host of supplementary eras, cultures measurements in between, perchance all is coincidental my hat will be eaten.

The next post will indicate the Maya “numbers” obtaining the Planet’s distance from the Sun, employing the NASA data

Peace
Derek

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