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Eclipse prediction and the GP (19 replies)

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Jacob gives us 8 / by the sekhed = 44/7

stonehenge gives us 56

the product is 352

divide by 14,666r gives 24

x 25 gives 366.666r

x 4 gives 1466.666r

the eclipse system at the GP?

Definition of the eclipse system:

Based on a book written by Professor Sir Fred Hoyle 'On Stonehenge ' The period in solar days that needs to be known in order to predict eclipses is 6585 and one third solar days.' This is the eclipse period and an eclipse system is any breakdown of this 6585 and 1/3 day period into measureable and consistent units.

The system I am referring to is the imperial chain in feet where one foot represents 100 units so 6600 units are represented. The 'eclipse unit' is 44/3 as an Egyptian fraction in metric 14.666r.

450 of these units is 6600 and as the Egyptians were very familiar with the ratio n/n-1 this gives 449 and x 44/3 is 6585 and 1/3 solar days exactly.

Other eclipse systems are regularly written about in particular the one based on one lunation of 29.53064 days but that is not the system I am referring to. The system 29.53064 reconciles to 14.666r x 2 = 29.333r as 29.53064 x 223 / 224.5.

This period of 14 and 2/3 days or 44/3 days occurs quite naturally in Hoyle's analysis and also on Fred Espanek's NASA website. These people are scientists and Thom referred to the monuments as remnants of scientific records that are still decipherable.

This naturally occurring period has a very interesting characteristic, it gives us Pi as 22/7.

44/3 /22 x 7 = 308/66 and subtracting the diameter from the circumference gives base 10 a number Thom identified as possibly universally sacred.

This is a rather unusual discovery that the ancients appear to have made and not only this.

When the number of days in an eclipse year are worked out the come to 365.2222r a very unusual number. When this number is subtracted from 365.25 days the imperial numbers are produced as follows.

365.25 - 365.222r = 0.0277777r or 1/36 as an Egyptian fraction and there are 36 inches in one yard.

36 x 10 two numbers already uncovered are 360 x 44/3 = 5280

360 divided by 0.00277777777r is also 5280 and 1/360 also happens to be the Babylonian 'She'

So as a culture you only need to have this explained to you to start using the imperial eclipse system.

5280 / 360 = 14.666r

1760 / 12 = 14.666r

Now 1760 is produced as the base perimeter of the GP when the height is 280 units this relationship is governed by the sekhed. Jacob has discovered this two dimensionally but it also works in three dimensions as indicated. The 44/7 circle becomes the four sided base of the GP.

The big problem is that the eclipse system produces the imperial numbers but not the units of length. Does the evidence suggest the ancients knew the modern circumference of the Earth 24901.5 imperial miles.

If Michell's canon of ancient measure is used yes it does

365.2222r x 360 x 1000 / 5280 = 24901.51515

Could Michell's system be an eclipse prediction system?

Using 365.2 solar days the circumference becomes 24900 miles

Using 366.666r solar days the circumference becomes 25000 miles

1466.666r solar days becomes 10000 miles an obvious eclipse prediction system based on 14.666r but in miles.

366.666r x 360 x 1000 = 132000000 imperial feet, this can be divided by a unit of 1.32 feet or 15.84 inches other units hidden within an eclipse prediction system.

So the suggestion is that the imperial system was first discovered then designed against the dimensions of the Earth with Thom's sacred base 10 built into the system.

The key units are 44/7 and 44/3 and added together they make the Royal Eclipse Cubit.

This analysis is also supported by Jim Wakefield's analysis of a Perfect Sphere using real Pi and much of the reasoning is derived from studying Jim's work in particular his 'Rollrights to Stonehenge Paper' that has been accepted after review by the European Archaeologist's representatives in Maastricht Holland last year.

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