2nd pyramid imperial measure (1 reply)

There is nothing new under the sun so if anyone has already come up with this please let me know but first time for me. I had taken the day off today so got busy on Flinders Petrie's 'pyramids and Temples' and wondered again as to the likely unit of measure used by the architect of the Second pyramid.

I do believe that the imperial system is a part of an ancient system of measures and in fact it works very well with Scottish Stone circles.

Now Ref the Second pyramid.

The imperial foot 12 inches and cubit of 18 inches fits perfectly. An ordinary cubit is 1.5 feet.

A number easily recognised comprise the first 3 numbers in pi 3.14. In this case the height of the pyramid in imperial cubits 314.

The height of the pyramid 471 imperial feet 5652 inches and 5652 inches/ 18 inches = 314 cubits. At the very least this is a coincidence and within the range error given by Petrie.

Because we believe the second pyramid is a 3 4 5 pyramid it is easy to work out the length of the base and in this case 471/4 = 117.75 and x 3 = 353.25 imperial feet x 2 = 706.5 imperial feet 8478 inches.

Now 706.5 imperial feet = 471 imperial cubits. Note the same number as the height of the pyramid 471 imperial feet.

After some fiddleing about I wondered what the perimeter of the base divided by the approximate for pi 3.14 would bring.

706.5 x 4 = 2826/3.14 = 900 exactly and a number I have come across many time before.

Jim